Quote: Originally posted by winpick3 on May 25, 2024
(2024-05-22) 558 - 008 = 550 (Played: 555 on 2024-05-25) (Mirror to a 0 is a 5)
As far as the 4's or 2's or whatever, you're right, maybe. I haven't focused on those.
I've only focused on what I've seen and the 3/8 concept, I saw, tested, back test, back
tested against ALL states, and works.
As far as what I mean by "version", it means, I can't tell you what digits will mirror or not
mirror, nor can I tell you what order, nor can I tell you "when" it will play. But when I say,
"it will play" That's because I've paid attention to details.
Let me give you an example. On 5/13 CALI played 063. Why? There's "some" reason it did.
The reason (I believe) is:
(2024-05-11) 735 - 699 = 036 (Played: 063 on 2024-05-13)
Two numbers minused from one another leaves an answer of 036, well CALI played 063.
Was this a coincidence or was there more to it?
What happens when we really understand the game we are playing and include the mirror aspects
(2024-05-02) 012 - 640 = 628 (Played: 231 on 2024-05-15)
Well, two numbers minused from one another (commonality), provide an answer of 628.
When we consider "all" the ways that ("versions") of how 628 can be played, and that includes
permutations as well is mirrors we are left with:
628, 682, 268, 286, 862, 826, 173, 137, 713, 731, 317, 371, 128, 182, 218, 281, 812, 821, 678, 687, 768, 786, 867, 876, 623, 632, 263, 236, 362, 326, 673, 637, 763, 736, 367, 376, 178, 187, 718, 781, 817, 871, 123, 132, 213, 231, 312, 321
And sure enough, 231, the "same" number CALI had drawn on 5/15, was in that possibility.
So when I say I can't tell you "which version", that's because all version of 628 would be like
628, 678, 673, 623, 128, 123, 173, 178
Each "unique" number, meaning the number does not contain a double in true or mirrored form,
produces 8 different ways a number can be played, when considering only the mirrors (version).
And then when you consider the permutations for each number (their placement), that means each
number can be played 6 different ways. So 8 (unique numbers) x 6 (permutations) = 48 numbers.
So a single unique number, can be played 48 different ways.
Now, when you involve a double or false double (mirrored number), that number is cut in half to 24 different ways.
Such as the case with this example:
(2024-05-18) 800 - 182 = 618
Again, two numbers subtracted from one another (commonality) leave an answer of "618".
When that 618 plays, it's going to play one of these "versions":
618, 681, 168, 186, 861, 816, 163, 136, 613, 631, 316, 361, 118, 181, 811, 668, 686, 866, 663, 636, 366, 113, 131, 311
If you were to break every single number down from 000 to 999 considering this method, you would
be amazed at just how many numbers are "covered" by just 1 number.
Again, I can't stress enough, how important it is to understand the game you are playing!
So does my approach work in regards to focusing on making sure it pays off? YES!
Let me show you how.
Let's take some basic numbers for example.
Bet Cost: $.50
Payout for win: $250
Now, I told you that when a triple plays, there's two numbers to ALWAYS play
after that and that is: 220, 200
Let's say you take and want to bet the "200". Great, now if you were to take into
consideration ALL the ways that "200" can be played "straight", you'd be looking at this:
200, 020, 002, 755, 575, 557, 700, 070, 007, 250, 205, 520, 502, 025, 052, 255, 525, 552, 750, 705, 570, 507, 075, 057
That's 24 numbers, because it's a "double" (00). So 24 x .50 per number = $12 per draw.
How many times can you bet this rack of numbers before you break even on $250?
Well, $12 per draw x 2 draws a day = $24 a day
$24 x 10 days = $240
So you would be able to bet this entire rack "STRAIGHT" for the next 10 days.
If any "version" of that number comes out within the next 10 days, you will win $250!
The question is will you profit from it? The closer to the time you start betting that rack,
is the larger profit side, and the closer to the 10 day mark, is the lesser profit side. But either way
you will have a "straight hit". When you play with this approach, you are NOT playing for a boxed hit,
instead you are playing for the straight - always!!!
Now what would be the cost if you play just one number from the "permutations" but still cover the entire rack?
That means the numbers you would play are:
200, 755, 700, 250, 255, 750
Now if you play those, you'd have to play them boxed to assure the hit, or you could play them straight but run
the risk of the number playing a different permutation. For example you played 200 straight and it came out 020.
So that still is only 6 numbers. So 6 numbers x .50 bet = $3
But this time you have to consider the "boxed" payout and not the straight payout. Some states will pay you $75
for a double playout on a .50 bet. It has to be a true double, like 200 and not 250. So again, do the math, and let's
assume CALI pays $75 on a double payout.
How many times can you play those 6 numbers, boxed before you hit $75?
$3 per draw x 2 draws a day = $6 per day
$6 per day / $75 = 12.5 days
So you can play those numbers, boxed for up to 12 1/2 days. If that number comes out, you will win boxed!
Again, the closer you are to the time you start betting, the more money you profit. Closer to the 12 day mark
less profit, but still profit.
So is it "viable" and can you use that strategy to actually win and make money? YES!
This is why it's important to pay attention to numbers and what the "system" does. The pick 3 lottery in my opinion
is really only made up of 500 numbers, 000 - 499. When we consider the mirrors, they take up the rest from 500 - 999.
And it's things like this:
200, 020, 002, 755, 575, 557, 700, 070, 007, 250, 205, 520, 502, 025, 052, 255, 525, 552, 750, 705, 570, 507, 075, 057
That prove that this has some value. Let me show you something. We will take 000 through 010
000 <-- 8 numbers
001 <-- 24 numbers
002 <-- 24 numbers
003 <-- 24 numbers
004 <-- 24 numbers
005 <-- 8 numbers
006 <-- 24 numbers
007 <-- 24 numbers
008 <-- 24 numbers
009 <-- 24 numbers
010 <-- 24 numbers
Now, if we start with 000, when we consider the mirrors, 005 is actually the same! So we can take those "8 numbers"
away from the 005 and remove 005 from the list.
000 <-- 8 numbers
001 <-- 24 numbers
002 <-- 24 numbers
003 <-- 24 numbers
004 <-- 24 numbers
006 <-- 24 numbers
007 <-- 24 numbers
008 <-- 24 numbers
009 <-- 24 numbers
010 <-- 24 numbers
Next number is 001, well, same thing with 006 AND 010, so now we removed 48 numbers from the
overall 1,000 list.
000 <-- 8 numbers
001 <-- 24 numbers
002 <-- 24 numbers
003 <-- 24 numbers
004 <-- 24 numbers
007 <-- 24 numbers
008 <-- 24 numbers
009 <-- 24 numbers
002 and 007, yep, same thing. So remove another 24 numbers. Let's break it all the way down
and this is the final list for just 000 - 010
000 <-- 8 numbers
001 <-- 24 numbers
002 <-- 24 numbers
003 <-- 24 numbers
004 <-- 24 numbers
So what started off with "208" numbers when you consider versions and permutations,
is now down to 104 numbers. Now, how many other numbers does this do this with?
All of them! I believe that final total is truly just 35 numbers when you truly consider
the versions and permutations. Again version = mirrored or not mirrored, permutations = placemements
When you see the lottery from this approach, it's not quite so overwhelming! You've got a 1 in 35 shot
to hit the right "version" and then when you consider just 1 boxed version which is 8 ways or 4 ways,
your odds still are significantly less than the 1 in 1,000 of hitting.
So overall yea, pick a number, play it's versions and permutations and stick with it, you will profit.