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pick 3 probabilityReply
Quote: Originally posted by Jake649 on May 20, 2004Quote: Originally posted by Bertil on May 20, 2004 By what formula does one calculate the odds of winning a pick3 type game if one buys 100 random tickets? Would it be 10%?Suppose the lottery sells only 5000 random tickets, what % of all numbers are likely to remain not sold?If every one of the 100 tickets is unique, then the odds of winning are exactly 10%. If you buy quick picks, you may have one or more duplicates, so the odds of winning are
May 20, 2004, 3:58 pm - Bertil - Lottery Discussion Forum

pick 3 probabilityReply
Quote: Originally posted by Bertil on May 20, 2004 By what formula does one calculate the odds of winning a pick3 type game if one buys 100 random tickets? Would it be 10%?Suppose the lottery sells only 5000 random tickets, what % of all numbers are likely to remain not sold?If every one of the 100 tickets is unique, then the odds of winning are exactly 10%. If you buy quick picks, you may have one or more duplicates, so the odds of winning are 9.5%.The formula is (1-p)^N where p = the probabili
May 20, 2004, 1:00 pm - Jake649 - Lottery Discussion Forum

Does GOOSE Get your Goat?Reply
He does get on my gander a bit. Is that an American expression too? Nothing sexist intended.I put his frequency of Posting down to wanting to have the Most Postings Record. With all the congratulations to the current record holder I think you may have spurred him on. I dare not say anthing political and hope others don't too as he obviously enjoys expressing himself if somewhat a little exubrently.GooseDon't be too offended; just moderate your rate of Posting to a reasonable level. I'm in roug
Mar 1, 2004, 7:14 pm - Colin F - Lottery Discussion Forum

Re: Formula for nobody winning is ((N-1)/N)^T where N is ...
Reply to Joe Schmoe's 4/17/2002 8:02:05 PM ET messageYour formula is creative, but I don't think it is correct!Assume there is a lottery with 1/10 odd of win (9/10 Odd of lose), and suppose 10 different tickets sold (all combinations). With your formula, chance of nobody win= ((N - 1)/N)^T= ((10 -1)/10^10= 0.347In simple logic, the winning ticket is sold. It is because all possible patterns sold. Therefore, the formula is false!Please participate and solve this math problem!Original Message:A fe
Apr 19, 2002, 1:08 pm - Gamma Ray - Lottery Discussion Forum

Formula for nobody winning is ((N-1)/N)^T where N is ...
A few messages ago I was wondering how to calculate the odds that nobody would win. Looks like it's ((N - 1)/N)^T where N is the total pool of numbers and T is the number of tickets sold. Let's apply this to the drawing just held: 2,744,447 won $1 with the odds of 1 in 62. So there were approximately 170,155,714 tickets sold. (76,275,359/76,275,360)^170,155,714 gives 10.75% chance that nobody wins.
Apr 17, 2002, 5:02 pm - Guest - Lottery Discussion Forum

plese help-software lottery line builderReply
yeah I know but I dont know how to find that lets say pattern that happens every year or two..this way odd even high low sum is happening 63% ,I calculate that..and lets say that I play 10 combinations ,that means 10 : 4 486 382 ,that means 1:486 382, if I play 20 comb that means 1: 240 000 instead 1:8 milion? is this true? and lets say that i play system 5/6 what are the odds than? does anyone know?
Apr 13, 2018, 7:20 pm - anakonda - Lottery Discussion Forum

Do Lottery Software program help YOU WIN lottery?Reply
There's nothing magic about software, a player has to have a strategy for improving his odds of winning before he or anyone else can write software that helps. Software can't do the thinking, the player has to do that and use software to instruct the computer to do things it does faster and more accurate than he can. If a player can record and calculate faster than a computer then he doesn't need any software or a computer.
Aug 29, 2014, 9:27 am - RJOh - Lottery Discussion Forum

New pick 7 daily game in TexasReply
So how do you calculate your true odds when they are doing a 55/10/7? I know that 55/10 = 29,248,649,430 to 1 and 10/7 = 120 to 1. So what formula do you use for 55/10/7?
Jan 5, 2014, 1:14 pm - TooTallLuke - Lottery Discussion Forum

Odds on OddsReply
If you calculate the distance from New York to California in inches you get an equivalent of MM/PB Jackpot Lottery odds: 175,000,000 to 1. At every inch is a lottery ticket with a different number on it. You have to pick the inch where the lucky ticket is located. Don't forget to pay the Toll Master $1.00 (MM) or $2.00 (PB) for every pick.
May 29, 2012, 1:12 pm - BlueDuck - Lottery Discussion Forum

Buying More Tickets Does Not Increase Your Odds.Reply
savagegoose beat me to it. 1 in 1,422.8 isn't quite the slam dunk Coin Toss seems to think it is. It's still extremely possible that you won't hit the jackpot. Chances are you'll earn a decent amount of money back, but you're still dropping almost $250K (almost $375K if you're doing Power Play) on a less-than-1% possibility of landing the big one. I'm not about to sit here and try to calculate the odds of breaking even, though it would make for a decent project for someone inclined to do so.
Mar 3, 2012, 2:00 am - mediabrat - Lottery Discussion Forum